Question

(0)
In the reaction 2P(g) + Q(9) = 3R(9) + S(g). If 2 moles each of P and Q taken initially in a 1 litre
flask. At equilibrium which is true :
(1) P] <[Q] (2) [P] = [Q] (3) [Q] = [R] (4) None of these​

Answer 1

Answer:

Option (1) [P] < [Q]

Explanation:

In the reaction 2 moles of P reacts with 1 mole of Q to give 3 moles of R and 1 mole of S

$2P+Q \rightarrow 3R+S$

If [R] = 3x and [S] = x

Then [P]=2-2x and [Q]=2-x

Thus at equilibrium the concentration of Q will be more than that of P

Thus

[P] < [Q]

Hope this helps.