Question

0 is the centre of a circle. Tangent TP & TQ of the circle intersect at point T in the

exterior of the circle. Point P & Q lie on the circle. IfPOQ = 120

then PTQ = ? ​

Answer 1

Answer:

283

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Answer 2

Answer:

60°

Step-by-step explanation:

angle POQ = 120°

In this OPTQ forms a quadrilateral

opposite angles of quadrilateral are supplementary

∠POQ + ∠PTQ = 180°

120° + ∠PTQ = 180°

∠PTQ = 180° - 120°

∠PTQ = 60°

Hope you get your answer