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0. P is any point in interior of AABC. Which of the following are true statement
(a) BP + PC > BC (b) AP + PC < AC
(c) AP + AB > BP
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Answer:
If P is an interior point of the triangle ABC, then prove that AC+BC>AP+BP?
Shuchi Saxena
Answered 2 years ago
Hello Mate!
Given : ABC is a triangle where p is interior point.
To prove : AC+BC>AP+BP
Proof : In triangle ABC
angle A > angle PAB [ Whole is greater than a part ] ____(1)
angle B > angle PBA [ Whole is greater than a part ] _____(2)
On adding (1) and (2) we get
angle A + angle B > angle PAB + angle PBA
BC + AC > PB + AP [ Side opp. to respective angles ]
Or
AC + BC > AP + PB
Q.ED
Have great future ahead!
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