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Construct a triangle ABC in which BC= 5cm, LB = 60and AC+AB =7.5
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Given : In Δ ABC , BC = 5am , AC + AB = 7.5cm and ∠ B = 60
∘
To construct : Δ ABC
Steps of construction :
1. Draw a ray BX and cut off a line segment BC = 5cm from it.
2. At B , construct ∠ XBY = 60∘ .
3. With B as center and radius = 7.5cm , draw an arc at meet BY at D.
4. Join CD.
5. Draw the perpendicular bisector of CD, by marking arc of length more than half of CD from both points C and D on both sides of it.
this line will be intersecting BD at A .
6. Join AC . Then , ABC is the required triangle .
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