Question

0. The slope of normal to the curve
y=log (loge x) at x = e is​

Answer 1

Step-by-step explanation:

• slope =dy/dx d(log(log x base e))/dx =1/log x base e ×x= keep x=e so slope =1/e

Answer 2

Answer:

Concept: applying derivatives

GIVEN: curve y=log (loge x) at x = e

TO FIND: slope

Step-by-step explanation:

y=log (loge x)

so, $\frac{dy}{dx}= d\frac{log(logx}{dx}$

so, $\frac{dy}{dx}= \frac{1}{logx}*\frac{1}{x}$

so, at x=e

$\frac{dy}{dx}$=$\frac{1}{e}$

therefore, the slope is 1/e.

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