Question

00:36
O 5. What is the molecular formula of the
compound formed when 4g of carbon and 19
of hydrogen react completely? (Atomic mass of
Carbon=12u Hydrogen =1u)​

Answer 1

Answer:

The compound has 54.5% Carbon, 9.23% Hydrogen. The remaining is Oxygen.

100 g of the compound will have 54.5 g C, 9.23 g H and 100−54.5−9.23=36.27 g O.

The atomic masses of C, H and O are 12 g/mol, 1 g/mol and 16 g/mol respectively.

The number of moles of C=

12 g/mol

54.5 g

=4.54 mol.

The number of moles of H=

1 g/mol

9.23 g

=9.23 mol.

The number of moles of O=

16 g/mol

36.27 g

=2.27 mol.

Mole ratio C:H:O=4.54:9.23:2.27=2:4:1

The empirical formula of the compound is C

2

H

4

O

The empirical formula mass =2(12)+4(1)+16=44 g/molMolar mass of the compound is 88 g/mol. It is twice the empirical formula mass of 44 g/mol.

The molecular formula of the compound is C

4

H

8

O

2

Answer 2

Answer:

The compound has 54.5% Carbon, 9.23% Hydrogen. The remaining is Oxygen.

100 g of the compound will have 54.5 g C, 9.23 g H and 100−54.5−9.23=36.27 g O.

The atomic masses of C, H and O are 12 g / mole, 1 g/mole and 16 g/mole respectively.

The number of moles of C=

12 g / mole

54.5 g

=4.54 mol.

The number of moles of H=

1 g / mole

9.23 g

=9.23 mol.

The number of moles of O=

16 g / mole

36.27 g

=2.27 mol.

Mole ratio C : H : O = 4 . 54 : 9 . 23 : 2 . 27 = 2 : 4 : 1

The empirical formula of the compound is C

C₄H₅N₂O

The empirical formula mass =2(12)+4(1)+16=44 g/mole. Molar mass of the compound is 88 g/mol. It is twice the empirical formula mass of 44 g/mol.

The molecular formula of the compound is C

carbon : 8

hydrogen : 10

oxygen : 2

nitrogen : 4

.

.

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