Question

0¹+1⁰+2¹+1²+0³+3⁰+2³ = (2)^p+(3)^q


find p and q​

Answer 1

Answer:

p=2 and q=2

explanation:

add everything and u get 13

therefore 2^2+3^2=13

Answer 2

0+1+2+1+0+1+8=2^p+3^q
13=4+9
13=2^2+3^2
So p= 2&q=2