Question

01. Considering a right circular cylinder and a right circular cone having equal radius and equal
height, arrange the following in descending order
a) Volume of the cylinder
b) Volume of the cone
c) Curved surface area of the cylinder
d) Curved surface area of the cone
The descending order is​

Answer 1

Step-by-step explanation:

Let the radius and height of cylinder and cone be r and h

Let slant height of cone be l

Curved surface area of cylinder=2πrh

Curved surface area of cone=πrl 

Ratio=CSA of coneCSA of cylinder=πrl2πrh=58

lh=54

Squaring both side

l2h2=2516

l2=(1625)h2

h2+r2=(1625)h2

r2=(169)h2

(hr)2=(43)2

h

Answer 2

Answer:

Answer:

The required probability is 1 .

Step-by-step explanation:

In any event , the sum of P(A) and P'(A) is always 1 .

Here , in a cricket match , the batswoman hits a boundary 25 times out of the 60 balls she plays .

The total number of balls ( Sample Space ) 60

Favourable Cases ( The no of times she hit a boundary ) > 25

Unfavourable Cases > 35

Probability that she hit a boundary > 25/60

Probability that she didn't hit a boundary > 35/60

Probability that she hit a boundary + Probability that she didn't hit a boundary

> 25/60 + 35/60

> 60/60

> 1

this is answer for your upper to upper question