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01. Two matrixes A and B are given. Express B^-1 through x and A.

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Answered by sharma78savita
2

Answer:

Matrix addition. If A and B are matrices of the same size, then they can be added. (This is similar to the restriction on adding vectors, namely, only vectors from the same space R n can be added; you cannot add a 2‐vector to a 3‐vector, for example.) If A = [aij] and B = [bij] are both m x n matrices, then their sum, C = A + B, is also an m x n matrix, and its entries are given by the formula

Step-by-step explanation:

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Answered by hukam0685
23

Step-by-step explanation:

Given:

A=\left[\begin{array}{ccc}3x&-4x&2x\\-2x&x&0\\-x&-x&x\end{array}\right]

B=\left[\begin{array}{ccc}x&2x&-2x\\2x&5x&-4x\\3x&7x&-5x\end{array}\right]

To find:

Express B^{-1} through x and A.

Solution:

Step 1: Take x common from A,so that to simplify the process

A=x\left[\begin{array}{ccc}3&-4&2\\-2&1&0\\-1&-1&1\end{array}\right]

B=x\left[\begin{array}{ccc}1&2&-2\\2&5&-4\\3&7&-5\end{array}\right]

Step 2: Multiply A and B

AB=x\left[\begin{array}{ccc}3&-4&2\\-2&1&0\\-1&-1&1\end{array}\right]x\left[\begin{array}{ccc}1&2&-2\\2&5&-4\\3&7&-5\end{array}\right]

thus

AB=x^2\left[\begin{array}{ccc}3&-4&2\\-2&1&0\\-1&-1&1\end{array}\right]\left[\begin{array}{ccc}1&2&-2\\2&5&-4\\3&7&-5\end{array}\right]

AB=x^2\left[\begin{array}{ccc}3(1)+(-4)(2)+2(3)&3(2)+(-4)(5)+2(7)&3(-2)+(-4)(-4)+2(-5)\\ (-2)(1)+1(2)+0(3)&(-2)(2)+1(5)+0(7)&(-2)(-2)+(1)(-4)+0(-5)\\(-1)(1)+(-1)(2)+1(3)&(-1)(2)+(-1)(5)+1(7)&(-1)(-2)+(-1)(-4)+1(-5)\end{array}\right]

on solving,one will get an identity matrix

AB=x^2\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]

Step 3: Find B inverse

AB=x^2I\\

A=x^2B^{-1}\\

B^{-1}=\frac{A}{x^2}\\

or

B^{-1}=Ax^{-2}\\

Final answer:

\boxed{\bold{B^{-1}=\frac{A}{x^2}=Ax^{-2}}}\\

Hope it helps you.

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