Question

011.
Write the values of sec Oʻ, sec
30°, sec 45 sec 60° and sec
90°. What happens to sec X
when x increases from O® to
90°?​

Answer 1

Step-by-step explanation:

sec0=1

\sec 30=\frac{2\sqrt3}{3}sec30=

3

2

3

\sec 45=\frac{\sqrt3}{2}sec45=

2

3

\sec 60=\sqrt 2sec60=

2

\sec 90=\inftysec90=∞

As we see that,

When x increases from 0 to 90 the sec x also increases from 1 to ∞.

Answer 2

$\huge{\bf{\red{Solution}}}$

$\sec(0 ) = \infty \\ \sec(30) = 2 \\ \sec(45) = \sqrt{2} \\ \sec(60) = \frac{2}{ \sqrt{3} } \\ \sec(90) = 1$

$\sec( x )= \infty - 1$

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