Question

013
Divide 56 in four parts in A.P. such that the ratio of their extreme (1" and 4") to the
product of means (2 and 3) is 5:6.
​

Answer 1

Answer:

hope this will help you

Step-by-step explanation:

Let the four parts be a−3d,a−d,a+d,a+3d

Sum, 4a=56

a=14

(a−d)(a+d)

(a−3d)(a+3d)

​  

=  

6

5

​  

 

6(a  

2

−9d  

2

)=5(a  

2

−d  

2

)

a  

2

=49d  

2

 

d=±2

For d=2,

Numbers are 8,12,16,20.