027. Two years ago a man was 6 times as old as his son. After 18 years he will be twice as old as his son.What will be the preseent age of the father and the son
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Answer:
let the age of son, two years ago be x
so the age of man two years ago = 6x
so, present age of son = x+2
present age of man = 6x+2
now, after 18 years,
age of son = x+2+18 = x+20
age of man = 6x+2+18 = 6x+20
A2Q, 6x+20 = twice of x+20
6x+20 = 2[x+20]
6x+20 = 2x+40
6x-2x= 40-20
4x = 20
x = 20/4
x = 5
so, present age of son = x+2 = 5+2 = 7
present age of man = 6x+2 = 6*5+2 = 32
hope it helps
have a nice day
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Given,
- Two years ago a man was 6 times as old as his son.
- After 18 years he will be twice as old as his son.
To Find,
- The Present age of father = ?
- The Present age of son = ?
Solution,
(Put the Value of a From the First Condition)
Therefore,
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