03 men and 06 women complete a work in 06 days.04 men 05 women complete the same work
on 05 days. So how many men are equal to 11 women for the same job.
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3 men and 6 women complete a work in 6 days.
This means the work takes 3*6 = 18 man days and 6*6 = 36 woman days.
4 men and 5 women complete the same work in 5 days.
This means the work takes 4*5 = 20 man days and 5*5 = 25 woman days.
difference in man days : 20-18 = 2
difference in woman days : 25-36 = -11
So adding 2 man days decreased the woman days by 11. Thus, men are equal to 11 women for this job.
This means the work takes 3*6 = 18 man days and 6*6 = 36 woman days.
4 men and 5 women complete the same work in 5 days.
This means the work takes 4*5 = 20 man days and 5*5 = 25 woman days.
difference in man days : 20-18 = 2
difference in woman days : 25-36 = -11
So adding 2 man days decreased the woman days by 11. Thus, men are equal to 11 women for this job.
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let productivity of a man = M amount / day
let productivity of a woman = W amount / day
total work amount = W = (3 M + 6 W) /day * 6 days
= (4 M + 5 W) /day * 5 days
=> 18 M + 36 W = 20 M + 25 W
=> 11 W = 2 M
Hence, 11 women do the same amount of work as 2 men do.
let productivity of a woman = W amount / day
total work amount = W = (3 M + 6 W) /day * 6 days
= (4 M + 5 W) /day * 5 days
=> 18 M + 36 W = 20 M + 25 W
=> 11 W = 2 M
Hence, 11 women do the same amount of work as 2 men do.
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