Math, asked by rajkumarisharma9012, 17 days ago

03. Which term of the series 1- 1/3 + 1/ 9 - 1 /27 +.... is 1/729 (a) 4 th (b) 5 th (c) 6 (th) ( d)7th​

Answers

Answered by testingpurpose152001
3

Answer:

Step-by-step explanation:

Let, the first term of the GP be a and common ratio be r

The general term of the GP be ar^{n-1}

Now, for the given GP, a=1 and r = -\frac{1}{3}

let, \frac{1}{729} be the nth term

so,

ar^{n-1} = \frac{1}{729}\\or,(-\frac{1}{3})^{n-1} = (-\frac{1}{3})^6\\or,n-1=6\\or,n=7

Thus, the 7th term of the given gp is 1/729

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