Math, asked by shivanisanesar9, 1 month ago

047. A and B together can do a certain job in 16 days.
A alone can do it in 32 days. If the contract for
the work is 4,000, then the share of B is
(A) 3000
(B) 2000
(C) 1000
(D) 34000​

Answers

Answered by asuafi
1

(D) 34000 is the answer. i think

Answered by dreamrob
0

The share of B is 2000.

Given:

Time taken by A and B to finish the job = 16 days

Time taken by A alone to finish the job = 32 days

Amount of contract for the work = 4000

To Find:

We need to find B's share

Solution:

Let the time taken by B to finish the job alone = B

Then, work done by B in 1 day = 1/B

Similarly, work done by A in 1 day = 1/32

Total work done in a day = 1/32 + 1/B

Work done in 16 days = 16/32 + 16/B

Let the total work be 1, then,

16/32 + 16/B = 1

16/B = 1 - 1/2

16/B = 1/2

B = 32

Thus, both A and B work at equal efficiency ⇒ A and B will get 2000 each.

Hence, the share of B is 2000.

#SPJ3

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