Question

06 A ball is thrown up with a speed of 10m/s-what
will be its finial velocity and why?
How high will it go before it begans tofall?
ii) How long will eit tóke to vedch that height?
ci)​

Answer 1

Explanation:

Maximum height = h= u²/2g

u being the initial velocity

using third equation

v² −u² =2g × height gained =2g× 2/h =gh

putting u² = 2gh in above equation from first equation we get v² − 2gh=gh or h = v²/3g = 10 × 10 / 10 =10 meter