Question

06 Draw a cide with centre cand radius 34
Draw any chowed Am Construct the perpen
dicular besector of AB and examine if
passes through C.
of​

Answer 1

Answer:

This implies that

x2+2ax=4x−4a−13

or

x2+2ax−4x+4a+13=0

or

x2+(2a−4)x+(4a+13)=0

Since the equation has just one solution instead of the usual two distinct solutions, then the two solutions must be same i.e. discriminant = 0.

Hence we get that

(2a−4)2=4⋅1⋅(4a+13)

or

4a2−16a+16=16a+52

or

4a2−32a−36=0

or

a2−8a−9=0

or

(a−9)(a+1)=0

So the values of a are −1 and 9.

Answer 2

Step-by-step explanation:

1) Draw a circle with centre C and radius 34 cm. 2) Draw any chord AB bar.

3) Taking A and B as centers and radius more than half of AB bar, draw two arcs which cut each other at P and Q.

4) Join PQ. Then PQ is the perpendicular bisector of AB bar.

5) This perpendicular bisector of AB bar passes through the centre C of the circle.