Question

06. The point (0, 0, k) lies outside the sphere
x2 + y2 + z2 - 62 + 8 = 0 if what is the condition for k​

Answer 1

Answer:

k=54

Step-by-step explanation:

x²+y²+z²-62+8=0

(0,0,k) lies

x=0, y=0, z=k

LHS = x²+y²+z²-62+8

= 0²+0²+k²-62+8

= 0+0+k-62+8

= k-54

k=54