08. A jet plane starts from rest with an acceleration of 3ms-2 and makes a run for 35s before taking off. What is the minimum length of the runway and what is the velocity of the jet at take off?.
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Answer:
(0,22.5),(150,0)
Equating line
(a−22.5)=
0−150
22.5−0
(5−0)
20(a−22.5)=−35
20a−450=−35
a=
20
−35+450
v
ds
dv
=
20
−35+450
∫
0
v
vdv=
20
1
∫
0
60
(−35+450)ds
2
v
2
=
20
1
(−
2
35
2
+450s)∣
0
60
v
2
=
10
1
(−5400+27000)
v=46.47m/s
Explanation:
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