Question

08 In a triangle ABC light angle at B
A B = 5cm and AC=10cm Determine
angle BAC and angle BCA.
​

Answer 1

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Given :-

In Δ ABC

AB =5cm

AC=10cm

To Find:-

Angle BAC and Angle BCA.

Therefore:-

InΔABC /_ B = 90°

AB =5cm

AC=10cm

Sin Thetha = AB /AC

= 5/10

=1/2

In /_BCA =Sin-¹ = ½=30°

=/_BCA =30°

=/_BAC=90° -/_BCA (30°)

=/_ BAC= 90°-30°=60°

So,

/_ BCA=30°

/_BAC= 60°

Answer 2

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