Question

08. In figure find the measurement of angle BCD
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Answer 1

Answer:

In ∆ABC

A=100° (given)

B=30° (given)

so, angle ABC +angle BAC + angle ACB =180° (angle sum property of ∆)

100°+30°+ ANGLE ACB = 180°

130° +ACB = 180°

ACB =180°-130°=50°

In ∆ BCD

C=50°

angle BCD + angle ACB =180°(linear pair)

50°+angle ACB =180°

angle ACB= 180°-50° =130°

HENCE, angle BCD=130°

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