Question

09:If a and B are the zeroes of :
polynomial 2-3x-x^2? then a-ß -​

Answer 1

Answer:

answer for the given problem is given

±√17

Answer 2

Answer:

0(zero)

Step-by-step explanation:

First arrange the given equation

=> -x^2-3x+2

D= b^2-4ac

=> -x^2-3x+2; a=-1, b=-3, c= 2

=> D= 9-4(-1)(2)

D= 9+8= 17

x=(-b+- √D)/2a

=>x=[-(-3) +- √17]/ 2(-1)

x= (3+-√17)/-2

x= -(3+√17)/2 , -(3-√17)/2

This means

a= -(3+√17)/2

B= -(3-√17)/2

Now ,

a-B = [-(3+√17)/2] - [-(3-√17)/2]

a-B = 0