Question

09A car starts from rest and moves along the was with constant
acceleration 5m/s for 8 seconds. If it then continue with consta
velocity, what distance will the car covers in 12s since it started to​

Answer 1

Answer:

u=0m/s

a=5m/s2

t=8sec.

v=u+at

v=0+5*8

v=40m/s

distance in 8 secs.

v2-u2=2as

40^2-0^2=2*5*s

1600=10s

s=1600/10=160m

distance in rest 4 secs.

40*4=160m

therefore total distance travelled=

160+260=320m

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