Question

(0Zn + KOH → K.ZnO+H,
(d) Fe,0, CO-Fe+CO,
(e) PbO + NH • Pb + H,O + N,
(0 Pb,O, PbO + 0
(8) PbS+0,- PbO + SO,
(h) S+H SO, SO +HO
(i) S + HNO -> H.SO, + NO +HO
() MnO, + HCI MnCI, + HO +CI,
(k) C + H,SOẠCO, + H,O + SO,
(1) KOH + CIKCI+KCIO+ H.O
(m) NO. + HO HNO, + HNO,
(n) Pb , + HCI-PbC1, +H.O+CI,
- HCI+ 0
(p) NaHCO, Na CO, +H0+ CO,
(0) H,0 +CI,
(9) HNO, H.S NO. + HO + S
(P + HNO, NO, +H.O+H, PO
(8) Zn + HNO, Zn(NO), +HONO​

Answer 1

Explanation:

your answer

all all reactions are concentrate

+ HNO ,NO3