Question

1) 0.1 m of aq. formic acid solution freeze at - 0.021°c. calculate it's degree of dissociation Kf = 1.86
k.kg / mol

2) what is the molar mass of solute if a solution prepared by dissolving 0.822 g it in 300 m dmcub a water has an o.p of 149 mmHg at 298k​

Answer 1

Answer:

The freezing point depression of a 0.109Maq. solution of formic acid is −0.21∘C. The equilibrium constant for the reaction is 1.44×10−x.

HCOOH(aq)⇌H+(aq)+HCOO⊖(aq)

Kf for water =1.86kgmol−1K

Value of x is:

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