Math, asked by pankajpegu31, 8 months ago

(k-3)x^2+6x+9=0 find the valir of k

Answers

Answered by govindbabu159

7

Answer:

K+ 1) x2–4Kx + 9 = 0, have real ... the equation for K = 3 (3 + 1)x2 – 4 × 3x + 9 = 0 4x2 – 12x + 9 = 0 4x2 – 6x – 6x + 9 ...

Answered by paultanuja09gmailcom

1

Step-by-step explanation:

$(k - 3) {x }^{2} + 6x + 9 = 0$ solution

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