1.0 gram of mg is burnt with 0.56gm oxygen in a closed vessel which reactant is left in excess and how much
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2Mg + O2 = 2 MgO
48.64 g of Mg reacts with 32 g of oxygen
1 g of Mg will consume 32/48.64 g of Oxygen = 0.658 g
But we have only 0.56 g of oxygen.
Therefore oxygen is the limiting reagent as it will get consumed completely and Mg is the excess reagent.
0.56g of oxygen need 0.56 x 48.658 /32 = 0.85 g of Mg
Excess reactant left is Mg of 0.15 g
48.64 g of Mg reacts with 32 g of oxygen
1 g of Mg will consume 32/48.64 g of Oxygen = 0.658 g
But we have only 0.56 g of oxygen.
Therefore oxygen is the limiting reagent as it will get consumed completely and Mg is the excess reagent.
0.56g of oxygen need 0.56 x 48.658 /32 = 0.85 g of Mg
Excess reactant left is Mg of 0.15 g
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