Question

1.0 mole of ethyl alcohol and 1.0 mole of acetic acid are mixed.At equillibrium 0.666 moleof the ester is present . The value of equillibrium constant is​

Answer 1

The given reaction will be as follows.

CH_{3}CH_{2}OH + CH_{3}COOH \rightarrow CH_{3}COOOCH_{2}CH_{3} + H_{2}OCH

3

CH

2

OH+CH

3

COOH→CH

3

COOOCH

2

CH

3

+H

2

O