Question

(1.01)^2-(0.98)^2 find using a^2-b^2=(a+b)(a-b)

Answer 1

$\huge\boxed{\texttt{\fcolorbox{red}{aqua}{Hey Mate!!!}}}$
$<b><i><font face=Copper black size=4 color=blue>$
Here is your answer

$(1.01) {}^{2} - (0.98) {}^{2} \\ \\ = (1.01 + 0.98)(1.01 - 0.98) \\ \\ = 1.99 \times 0.03 \\ \\ = 0.0597$

$\large{\red{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\underline{\underline{\underline{Hope\:it\:helps\: you}}}}}}}}}}}}}}}$

$\huge\boxed{\texttt{\fcolorbox{Red}{yellow}{Be brainly!!!}}}$

$<marquee>$
$\huge\bf{\red{\huge{\bf{@.....rajeev378}}}}$