Question

1.02 g of metallic oxide contain 0.54 g of metal. Calculate the equivalent weight of the metal​

Answer 1

Answer:

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Explanation:

Given: 1.020g metallic oxide mass

0.540g mass of metal

So the mass of oxygen in oxide will be=1.020−0.540=0.480g

Equivalent mass of metal=

0.480

0.540

× 8=9.0g

According to Dulong and Petit's law,

Approx. atomic mass =(6.4/sp heat)=(6.4/0.216)=29.63,

Valency of the metal = at.mass/eq.mass =29.63/9≈3

Hence the formula of the oxide is M2o2