Question

1.0g of a gas occupies 0.56 litres at STP. Calculate the molecular weight of the gas. (R=0.832 Latm Mot'k')​

Answer 1

Answer:

405.6 gram

Explanation:

we use here ideal gas equation

PV = NRT

ALSO we know that N mean no of moles = given mass ÷ molar mass

and at stp pressure and temperature we can take 1 atm and 273k

pv = nrt

pv= given mass × r × t /molar mass

1×.560 = 1.0 ×.832×273 ÷molar mass

molar mass = 1.0×.832×273÷560 = 405.6 grams