Question

1÷[1+1{1+1÷(1+1/3)}] method of bodmas​

Answer 1

1 ÷ (1+1(1+1 ÷ (1+1/3)))

1 ÷ (1+1(1+1 ÷ (4/3)))

1 ÷ (1+1(1 +1 × 3/4)))

1 ÷ (1+1(1 + 3/4)))

1 ÷ (1+1(7/4))

1 ÷ (1+7/4)

1 ÷ (11/4)

= 4/11

i hope it helps