Question

(-1)^1+(-1)^2..............+(-1)^2020​

Answer 1

$\Large{\underline{\underline{\bf{Solution :}}}}$

We have to find the value of

$\sf{(-1)^1 + (-1)^2 ............. + (-1)^{2020}}$

So, we know that,

$\Large{\implies{\boxed{\boxed{\sf{(-1)^1 = -1}}}}}$

And,

$\Large{\implies{\boxed{\boxed{\sf{(-1)^2 = 1}}}}}$

_____________[Put Values]

We get,

$\sf{→(-1)^1 + (-1)^2 ............. + (-1)^{2020}} \\ \\ \sf{→ \cancel{(-1)} + \cancel{1} + \cancel{(-1)} + \cancel{1} ....... \cancel{(-1)} + \cancel{1}} \\ \\ \bf{Similarly \: all \: will \: be \: cutted} \\ \\ \sf{→0} \\ \\ \sf{\therefore \: 0 \: is \: the \: correct \:answer}$

$\Large{\red{\boxed{\blue{\boxed{\green{\boxed{\orange{\boxed{\pink{\boxed{\purple{\boxed{\gray{\boxed{\sf{\color{yellow}{Jai \: Shree \: Krishna}}}}}}}}}}}}}}}}}$

Answer 2

Zero is the right answer...