Question

1/(1+√2) + 1/(√2+√3) + 1/(√3+√4)+......+1/√99+√100 = ?​

Answer 1

Answer:

9

Step-by-step explanation:

1/(1+√2)+1/(√2+√3)+.....+1/(√99+√100)

=(√2-1)+(√3-√2)+(√4-√3)+......+(√100-√99)

=√100-1

=10-1

=9

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