Math, asked by LearnSomething1789, 11 months ago

1/1.2.3+3/2.3.4+5/3.4.5+... Test the convergence

Answers

Answered by lavkushhome07
16

Answer:

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Answered by SejalMaisheri
5

Answer:

 \sum \frac{2n + 1}{n(n + 1)(n + 2)}

The series is convergent

Step-by-step explanation:

1) Find the nth term of the series.

note that in the numerator the sequence is 1,3,5..

so the nth term will be 2n+1

And in the denominator the sequence is 1.2.3, 2.3.4,...

so the nth term will be n(n+1)(n+2)

so the nth term of given series Σan is given as

a_n =  \frac{2n + 1}{n(n + 1)(n + 2)}

2) Consider another series with nth term

 b_n =  \frac{1}{ {n}^{2} }

3) Find the ratio of nth term of both the series

 \frac{a_n}{b_n}  =  \frac{(2n + 1)( {n}^{2}) }{n(n + 1)(n + 2)}

 \frac{a_n}{b_n}  =  \frac{ {n}^{3}(2 +  \frac{1}{n}  )}{ {n}^{3} (1 +  \frac{1}{n} )(1 +  \frac{2}{n}) }

 \frac{a_n}{b_n}  =  \frac{2 +  \frac{1}{n} }{(1 +  \frac{1}{n} )(1 +  \frac{2}{n}) }

4) Find it's limit say l

l = \lim_{n \to  \infty } \frac{a_n}{b_n} =  \frac{2}{(1)(1)}   = 2

 \lim_{n \to  \infty } \frac{1}{n}  = 0

5) Using the test that if l is not equal to zero or infinity then both the series behave same, here as the limit is 2 both the series will behave same.

6) We know that series Σbn is convergent by p-test as p= 2 >1

7) Therefore the the series Σan will also be convergent.

Therefore the Series

 \sum \frac{2n + 1}{n(n + 1)(n + 2)} is convergent.

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