Math, asked by Kigili3771, 11 months ago

A girl is twice her sisters age .five years hence the product for their ages is 375.find their present age

Answers

Answered by SidhantVerma77
0

Step-by-step explanation:

Let the sister's age be x

Therefore, girl's age = 2x

X+5×2x+5 = 375

X+5×2x = 370

X×2x = 365

2x² = 365

X² = 182.5

X = square root of 182.5. (answer).

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Answered by vyshnavijangam
1

Answer:

et "x" be the age of sister

"2x" be the age of girl

Five years hence,

age of sister  =  x + 5

Age of girl  =  2x + 5

Product of their ages  =  375

(x + 5)(2x + 5 )  =  375

2x2 + 5x + 10x + 25 - 375  =  0

2x2 + 15x - 350  =  0

2x2 - 20x + 35x - 350  =  0

2x(x - 10) + 35(x -10)  =  0

(2x + 35)(x - 10)  =  0

 x = 10

Hence the age of sister is 10 years, age of girl  =  2(10)  =  20 years.

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