Question

1/(1+√2)-√3 rationalise the denominator​

Answer 1

Answer:

$\frac{1}{1 + \sqrt{2} - \sqrt{3} } \\ \frac{1}{1 + \sqrt{2} - \sqrt{3} } \times \frac{1 + \sqrt{2} + \sqrt{3} }{1 + \sqrt{2} + \sqrt{3} } \\ = \frac{1 + \sqrt{2} + \sqrt{3}}{ {(1 + \sqrt{2}) }^{2} - {( \sqrt{3}) }^{2} } \\ = \frac{1 + \sqrt{2} + \sqrt{3}}{1 + 2 + 2 \sqrt{2} - 3} \\ = \frac{1 + \sqrt{2} + \sqrt{3}}{2 \sqrt{2} } \\ = \frac{1 + \sqrt{2} + \sqrt{3}}{2 \sqrt{2} } \times \frac{ \sqrt{2} }{ \sqrt{2} } \\ = \frac{ \sqrt{2} + 2 + \sqrt{6} }{4}$

Answer 2

Answer:

above answer is correct

Step-by-step explanation:

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