Question

1 1
2.
If(21.4)" = (0.00214)' = 100, then the value of
is
1/aminus1/b​

Answer 1

Answer:

The answer is 2.

Step-by-step explanation:

Given that

(21.4)a=(0.00214)b=100

(21.4)a=100,(0.00214)b=100

Applying log on both the sides, we get

a=log21.4​100,b=log0.00214​100

∴a1​−b1​=log21.4​1001​−log0.00214​1001​, ∵ [loga​b=logb​a1​]

⇒a1​−b1​=log100​21.4−log100​0.00214

∴a1​−b1​=log100​0.0021421.4​=log100​1002=2log100​100=2

Answer 2

Answer:

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