Question

2. If the temperature of water changes by
10 °C on giving 300 cal of heat, what is the
mass of water?
give the answer with full explanation ​

Answer 1

Answer:

The heat absorbed is calculated by using the specific heat of water and the equation ΔH=cp×m×ΔT. 4. Water is vaporized to steam at 100oC. The heat absorbed is calculated by multiplying the moles of water by the molar heat of vaporization.

Explanation:

Amount of the heat given to water due to rise in temperature can be computed easily by using the formula as follows:

Q=m×ΔT

Where m is mass of the water and

ΔT is the change in temperature. This formula is only applicable for water as Specific heat of water is s=1cal/g  

0

C

Given Q =  300 cal

Change in temperature, ΔT=10 degree celsius

Thus,

m=Q/del T

m=300/10

m=30gram

Answer 2

Answer:

300= M*1*10

M = 30 g

Explanation:

Q(heat supplied) = M(mass) C(specific heat capacity) ∆T(change in temperature)