Question

1+1=3 but 1+1=2 how is it possible??????

Answer 1

Answer:

by mistake

Step-by-step explanation:

hahahahhahahahah

Answer 2

No it can't be 3. But it can be 4. Let's look into it,

let's consider (1+1)^2

[ a^2+2ab+b^2 = (a+b)^2 ] since, a = 1 & b = 1

• No it can't be 3. But it can be 4.Let's look into it,let's consider (1+1)^2[ a^2+2ab+b^2 = (a+b)^2 ]since, a = 1 & b = 1(1)^2+2×1×1+(1)^2
• 1+2+1
• 4

Therefore, it is your solution.

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