Question

1
1
(5)
+
2(3x + 4y) 5(2x - 3y) 4
5
2.
3
(3x + 4y) (2x - 3y)
2​

Answer 1

Answer:

Solution

like this you can make

2(3x+4y)

1

+

5(2x−3y)

1

=

4

1

;

(3x+4y)

5

−

(2x−3y)

2

=−

2

3

3x+4y

1

=u,

2x−3y

1

=v

2

1

u+

5

1

v=

4

1

⇒ 10u+4v=5.....(I)

5u−2v=

2

−3

⇒ 10u−4v=−3. ......(II)

(I) + (II)

20u=2

⇒u=

10

1