Question

(1/1+a+b^-1)+(1/1+b+c^-1)+(1/1+c+a^-1)=1 if abc=1

Answer 1

Answer:

2+a+b+c+ab+bc+ca

Step-by-step explanation:

(1/1+a+1/b) + (1/1+b+1/c) + (1/1+c+1/a)

(b+ab+1)/b + (c+bc+1)/c + (a+ca+1)/a

By taking LCM

(3abc+a²bc+ab²c+abc²+ab+bc+ca)/abc

Taking abc common in numerator

[abc(2abc+a+b+c) + ab +bc + ca] / abc

given abc =1

[1(2x1 +a+b+c)+ab+bc+ca] /1

2+a+b+c+ab+bc+ca.