Math, asked by jbvbjkhhh8465, 10 months ago

(1-1/n+1)+(1-2/n+1)+(1-3/n+1).....(1-n/n+1)

Answers

Answered by pammidinesh999
0

Answer:

n /2

Step-by-step explanation:

(1-1/n+1)+(1-2/n+1)+(1-3/n+1).....(1-n/n+1)

we will have n 1s so

n - [ 1 / n+1 ( 1 +2+3+...........n )]

n - [ 1 / n+1 ( n*n+1 / 2 )]

n - n/2 = n/2

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