Question

1
1. Rationalise the denominator of
√7-√6​

Answer 1

Answer:

Step-by-step explanation:

If it's $\frac{\sqrt{7} }{\sqrt{6} }$

$\frac{\sqrt{7} }{\sqrt{6} } *\frac{\sqrt{6} }{\sqrt{6} }$

$\frac{\sqrt{42} }{6}$  you can't divide em by each other

Answer 2

Answer:

Step-by-step explanation:

=      1      

    (√7-√6)

=       1(√7+√6)    

   (√7-√6)(√7+√6)

=      √7+√6        

    (√7)sq-(√6)sq

=       √7+√6        

         7- 6

=        √7+√6      

            1

=        √7+√6   (rationalised)

disclaimer: you have asked to rationalise denominator of √7-√6 but this equation is ralionalised properly

so we have solved the similar question that matches your question.

sq means square root like this $(\sqrt{7} )^{2}-( \sqrt{6})^{2}$  which we have included in step 3 pls note it

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