Question

1/1+sinA + 1/1-sinA= 2secA​

Answer 1

Answer:

L.H.S,,,

1/1+sinA + 1/1-sinA

1-sinA + 1 +sinA / 1 - sin²A

2/cos²A [ sin²A + cos²A = 1 ]

= 2 × 1/cos²A { 1/cosA = secA }

= 2 × sec²A

= 2sec²A

= RHS

hope it helps you