Question

1
10. Find the increase in kinetic energy of a
body of mass 500 g, when its speed
increases from 2 m s' to 4 m s.
500
​

Answer 1

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Your solution ⤵⤵⤵

Kinetic energy = mv²/2

M= 0 .5 kg

when v= 2

$kinetic \: energy \: \\ = > \frac{1}{2} \times 0.5 \times 2 \times 2 = 1 \: joule$

When V = 4

$ke \: = \frac{1}{2} \times 0.5 \times 4 \times 4</em></p><p><em>=</em><em>></em><em> </em><em>\</em><em>:</em><em>4 \: joules$

Difference between Kinetic energy

=> 4 - 1= 3 joules

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Answer 2

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