Plz find the solution.....
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THIS QUESTION CAN BE SOLVED BY FACTORISATION
Consider, x2 – x –a(a + 1) = 0
⇒ x2 – ax – x + ax – a(a + 1) = 0
⇒ x2 – x(a +1) + ax – a(a + 1) = 0
⇒ x[x – (a +1)] + a[x – (a + 1)] = 0
⇒ [x – (a +1)] [x+ a] = 0
⇒ [x – (a +1)] = 0 or [x+ a] = 0
∴ x = (a +1) or x = –a
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njgss:
from where u taken -ax and + ax two times
it is property
we need to get 1 by cancellation so it is
got it
why we need to get 1
it needs to be cancelled
u plz solve my new question
plz
ok
sure but later
Answered by
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Step-by-step explanation:
THIS QUESTION CAN BE SOLVED BY FACTORISATION
Consider, x2 – x –a(a + 1) = 0
⇒ x2 – ax – x + ax – a(a + 1) = 0
⇒ x2 – x(a +1) + ax – a(a + 1) = 0
⇒ x[x – (a +1)] + a[x – (a + 1)] = 0
⇒ [x – (a +1)] [x+ a] = 0
⇒ [x – (a +1)] = 0 or [x+ a] = 0
∴ x = (a +1) or x = –a
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