Question

1. 10 gm of ice at 0°C is mixed with 50 gm of water at 12°C.What will be the final temperature of the mixture?​

Answer 1

Answer:

Explanation:

It takes about 334 Joules - about 80 calories - to melt a gram of ice into water at 0 C So 10 grams will require 800 calories.

To cool 50 grams of water through 12 degrees C you require 600 calories. So the result will be a mixture of ice and water at 0C

600 calories will melt only 600/80 or 7.5 grams of ice to water. The result will be 57.5 grams of water at 0C with 2.5 grams of ice floating in it.