Math, asked by ShreyaMurali, 7 months ago

(1/10!)+(x/2*11!)=252/12 find x

Answers

Answered by pulakmath007
2

SOLUTION

GIVEN

 \displaystyle \sf{ \frac{1}{10!} +  \frac{x}{2.11!}   =  \frac{252}{12!} }

TO DETERMINE

The value of x

EVALUATION

 \displaystyle \sf{ \frac{1}{10!} +  \frac{x}{2.11!}   =  \frac{252}{12!} }

 \displaystyle \sf{ \implies \frac{12 \times 11}{12 \times 11 \times 10!} +  \frac{6 \times x}{6 \times 2 \times 11!}   =  \frac{252}{12!} }

 \displaystyle \sf{ \implies \frac{132}{ 12!} +  \frac{6 x}{12!}   =  \frac{252}{12!} }

 \displaystyle \sf{ \implies \frac{132 + 6x}{ 12!}  =  \frac{252}{12!} }

 \displaystyle \sf{ \implies 132 + 6x = 252 }

 \displaystyle \sf{ \implies 6x = 120}

 \displaystyle \sf{ \implies x = 20}

FINAL ANSWER

The required value of x = 20

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