Question

1.
10 years ago the age
of mother is a 4
times the age of her daughter she would
be then the ratio of their ages after 3
years is 15f:7 find their present age​

Answer 1

Answer:

Let the present ages of the mother and daughter be x and y respectively.

X= mother

Y= daughter

So the first equation (10 years ago ) is as follows :

x-10=4(y-10)

So, x-10=4y-40

x=4y-30 …1

Now coming to the second equation :

x+10=2(y+10)

So,x+10=2y+20

x=2y+10 …2

From 1 and 2

2y+10=4y-30

2y=40 y=20

Therefore the daughter’s age is 20